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4NaOH	+	SbCl₃	→	3NaCl	+	Na [Sb (OH)₄]
sodium hydroxide				sodium chloride		Sodium tetrahydroxoantimonate (III)
(đặm đặc)

4		1		3		1	Hệ số
							Nguyên - Phân tử khối (g / mol)
							Số mol
							Khối lượng (g)

Lintlha tse ling mabapi le equation 4NaOH + SbCl₃ → 3NaCl + Na [Sb (OH)₄]

What is reaction condition of NaOH (sodium hydroxide) reacts with SbCl3 () ?

Ha ho na tlhahisoleseling e fumanoeng bakeng sa equation ena ea lik'hemik'hale

Tlhaloso: Maemo a loketseng a tikoloho bakeng sa karabelo, joalo ka mocheso, khatello, li-catalysts, le solvent. Li-Catalysts ke lintho tse potlakisang lebelo (lebelo) la karabelo ea lik'hemik'hale ntle le ho jeoa kapa ho fetoha karolo ea sehlahisoa sa pheletso. Li-catalyst ha li na phello maemong a tekano.

Kamoo likarabelo li ka etsahalang le ho hlahisa NaCl (sodium chloride) le Na[Sb(OH)4] (Sodium tetrahydroxoantimonate(III))) ?

In a full sentence, you can also say NaOH (sodium hydroxide) reacts with SbCl3 () and produce NaCl (sodium chloride) and Na[Sb(OH)4] (Sodium tetrahydroxoantimonate(III))

Phenomenon kamora NaOH (sodium hydroxide) e sebetsana le SbCl3 ()

Tekano ena ha e na tlhahisoleseling efe kapa efe e mabapi le ketsahalo.

Maemong ana, o hloka feela ho sheba ho bona hore na ntho ea sehlahisoa ke eng Na [Sb (OH) 4] (Sodium tetrahydroxoantimonate (III)), e hlahang qetellong ea karabelo.

Kapa haeba ho na le e 'ngoe ea lintho tse latelang tse sebetsang SbCl3, ea nyamela

Ke lintlha life tse ling tsa bohlokoa tseo u lokelang ho li tseba mabapi le karabelo

Ha re na lintlha tse ling mabapi le ts'ebetso ea lik'hemik'hale tsena.

Lihlopha tsa equation

Lipotso tse ling tse amanang le karabelo ea lik'hemik'hale 4NaOH + SbCl₃ → 3NaCl + Na [Sb (OH)₄]

Lipotso tse amanang le sehlahisoa Na[Sb(OH)4] (Sodium tetrahydroxoantimonate(III))

Na[Sb(OH)4] () e na le lik'hemik'hale life le sebopeho sa 'mele? Ke liphetoho life tsa lik'hemik'hale tse nang le Na[Sb(OH)4] (Sodium tetrahydroxoantimonate(III))) e le sehlahisoa?

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4NaOH + SbCl3 = 3NaCl + Na[Sb(OH)4] | Equation ea lik'hemik'hale

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Litekanyo le NaOH e le reactant

sodium hydroxide

2NaOH + NH₄HONA₄ → lihora tse 2₂O + Na₂SO₄ + NH₃ NaOH + CH₃-CH₂-KO-CH₂-C₆H₅ → C.₆H₅CH₂OH + CH₃CH₂KOANNA NaOH + C₆H₅Br → C₆H₅ONa + H₂O + NaBr Sheba li-equations tsohle le NaOH joaloka reactant

Litekanyo le SbCl3 e le reactant

3H₂O + 2SbCl₃ → 6HCl + Sb₂O₃ 3H₂S + 2SbCl₃ → 6HCl + Sb₂S₃ Cl₂ + SbCl₃ → SbCl₅ Sheba li-equations tsohle le SbCl3 joaloka reactant

Lipalo le SbCl3 e le sehlahisoa

2SbF₃ + 3SOCl₂ → 2SbCl₃ + 3SOF₂ 3CCl₄ + 3SbF₃ → 3CCl₂F₂ + 2SbCl₃ SbCl₅ → Cl₂ + SbCl₃ Sheba li-equations tsohle le SbCl3 e le sehlahisoa

Lipalo le SbCl3 e le sehlahisoa

3CCl₄ + 3SbF₃ → 3CCl₂F₂ + 2SbCl₃ SbCl₅ → Cl₂ + SbCl₃ 2SbF₃ + 3SOCl₂ → 2SbCl₃ + 3SOF₂ Sheba li-equations tsohle le SbCl3 e le sehlahisoa

NaOH + SbCl3 = NaCl + Na[Sb(OH)4] | E leka-lekane | Lintlha tsa Karabelo ea Lik'hemik'hale

sodium hydroxide + = sodium chloride + Sodium tetrahydroxoantimonate(III) |

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