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NaOH	+	C₆H₅Br	→	C₆H₅ONa	+	H₂O	+	NaBr
sodium hydroxide						metsi		bromide ea sodium
(lng)		(lng)		(rn)		(lng)		(rn)
(không màu)		(không màu)		(trắng)		(không màu)		(trắng)
1		1		1		1		1	Hệ số
									Nguyên - Phân tử khối (g / mol)
									Số mol
									Khối lượng (g)

Lintlha tse ling mabapi le equation NaOH + C₆H₅Br → C₆H₅ONa + H₂O + NaBr

What is reaction condition of NaOH (sodium hydroxide) reacts with C6H5Br () ?

Ha ho na tlhahisoleseling e fumanoeng bakeng sa equation ena ea lik'hemik'hale

Tlhaloso: Maemo a loketseng a tikoloho bakeng sa karabelo, joalo ka mocheso, khatello, li-catalysts, le solvent. Li-Catalysts ke lintho tse potlakisang lebelo (lebelo) la karabelo ea lik'hemik'hale ntle le ho jeoa kapa ho fetoha karolo ea sehlahisoa sa pheletso. Li-catalyst ha li na phello maemong a tekano.

Lits'ebetso li ka etsahala joang 'me tsa hlahisa C6H5ONa () le H2O (metsi) le NaBr (sodium bromide) ?

Ka polelo e feletseng, u ka boela ua re NaOH (sodium hydroxide) e sebetsana le C6H5Br () mme e hlahisa C6H5ONa () le H2O (metsi) le NaBr (sodium bromide)

Phenomenon kamora NaOH (sodium hydroxide) e arabela ka C6H5Br ()

Tekano ena ha e na tlhahisoleseling efe kapa efe e mabapi le ketsahalo.

Maemong ana, o hloka feela ho sheba ho bona hore na ntho ea sehlahisoa ke eng NaBr (sodium bromide), e hlahang qetellong ea karabelo.

Kapa haeba ho na le e 'ngoe ea lintho tse latelang tse sebetsang C6H5Br, ea nyamela

Ke lintlha life tse ling tsa bohlokoa tseo u lokelang ho li tseba mabapi le karabelo

Ha re na lintlha tse ling mabapi le ts'ebetso ea lik'hemik'hale tsena.

Lihlopha tsa equation

Lipotso tse ling tse amanang le karabelo ea lik'hemik'hale NaOH + C₆H₅Br → C₆H₅ONa + H₂O + NaBr

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NaOH + C6H5Br = C6H5ONa + H2O + NaBr | Equation ea lik'hemik'hale

Palo eohle ea linaleli tsa sengoloa sena ke: 5 in 1 tekolo botjha

Rating: 5 / 5 linaleli

Litekanyo le NaOH e le reactant

sodium hydroxide

NaOH + C₆H₅Br → C₆H₅ONa + H₂O + NaBr NaOH + CH₃-CH₂-KO-CH₂-C₆H₅ → C.₆H₅CH₂OH + CH₃CH₂KOANNA HCI + NaOH → H₂O + NaCl Sheba li-equations tsohle le NaOH joaloka reactant

Linomoro le C6H5Br joalo ka reactant

NaOH + C₆H₅Br → C₆H₅ONa + H₂O + NaBr 2Na + C₆H₅Br + CH₃Br → C₆H₅CH₃ + 2NaBr KOH + C₆H₅Br → Sheba li-equation tsohle le C6H5Br joalo ka reactant

Lipalo le C6H5Br e le sehlahisoa

Br₂ + C₆H₆ → C.₆H₅Br + HBr Br₂ + C₆H₆ → HCl + C₆H₅Br C₆H₅OH + HBr → H₂O + C₆H₅Br Sheba li-equation tsohle le C6H5Br e le sehlahisoa

Lipalo le C6H5Br e le sehlahisoa

Br₂ + C₆H₆ → C.₆H₅Br + HBr Br₂ + C₆H₆ → HCl + C₆H₅Br C₆H₅OH + HBr → H₂O + C₆H₅Br Sheba li-equation tsohle le C6H5Br e le sehlahisoa

Lipalo le C6H5Br e le sehlahisoa

Br₂ + C₆H₆ → C.₆H₅Br + HBr Br₂ + C₆H₆ → HCl + C₆H₅Br C₆H₅OH + HBr → H₂O + C₆H₅Br Sheba li-equation tsohle le C6H5Br e le sehlahisoa

NaOH + C6H5Br = C6H5ONa + H2O + NaBr | E leka-lekane | Lintlha tsa Karabelo ea Lik'hemik'hale

sodium hydroxide + = + metsi + bromide ea sodium |

Litaba Ke 5% feela ea BAAHI e tla tseba

Lintlha tse ling mabapi le equation NaOH + C₆H₅Br → C₆H₅ONa + H₂O + NaBr

What is reaction condition of NaOH (sodium hydroxide) reacts with C6H5Br () ?

Lits'ebetso li ka etsahala joang 'me tsa hlahisa C6H5ONa () le H2O (metsi) le NaBr (sodium bromide) ?

Phenomenon kamora NaOH (sodium hydroxide) e arabela ka C6H5Br ()

Ke lintlha life tse ling tsa bohlokoa tseo u lokelang ho li tseba mabapi le karabelo

Lihlopha tsa equation

Lipotso tse ling tse amanang le karabelo ea lik'hemik'hale NaOH + C₆H₅Br → C₆H₅ONa + H₂O + NaBr

Lipotso tse amanang le reactant NaOH (sodium hydroxide)

Lipotso tse amanang le reactant C6H5Br ()

Lipotso tse amanang le sehlahisoa C6H5ONA ()

Lipotso tse amanang le sehlahisoa H2O (metsi)