KOH + Na2Cr2O7 = H2O + Na2CrO4 + K2CrO4 | Balanced | Chemical Reaction Details

Lintlha tse ling mabapi le equation 2KOH + Na₂Cr₂O₇ → H₂O + Na₂CrO₄ + K₂CrO₄

Boemo ba karabelo ea KOH (potassium hydroxide) ke bofe ka Na2Cr2O7 (Sodium dichromate; sodium bichromate; Dichromic acid disodium letsoai) ?

Ha ho na tlhahisoleseling e fumanoeng bakeng sa equation ena ea lik'hemik'hale

Tlhaloso: Maemo a loketseng a tikoloho bakeng sa karabelo, joalo ka mocheso, khatello, li-catalysts, le solvent. Li-Catalysts ke lintho tse potlakisang lebelo (lebelo) la karabelo ea lik'hemik'hale ntle le ho jeoa kapa ho fetoha karolo ea sehlahisoa sa pheletso. Li-catalyst ha li na phello maemong a tekano.

Lits'ebetso li ka etsahala joang le ho hlahisa H2O (metsi) le Na2CrO4 (Sodium chromate; Sodium chromate(VI); Chromic acid disodium salt) le K2CrO4 () ?

KOH e sebetsana le sodium dichromate

In a full sentence, you can also say KOH (potassium hydroxide) reacts with Na2Cr2O7 (Sodium dichromate; Sodium bichromate; Dichromic acid disodium salt) and produce H2O (water) and Na2CrO4 (Sodium chromate; Sodium chromate(VI); Chromic acid disodium salt) and K2CrO4 ()

Phenomenon kamora KOH (potassium hydroxide) e sebetsana le Na2Cr2O7 (Sodium dichromate; sodium bichromate; Dichromic acid disodium letsoai)

Ke lintlha life tse ling tsa bohlokoa tseo u lokelang ho li tseba mabapi le karabelo

Ha re na lintlha tse ling mabapi le ts'ebetso ea lik'hemik'hale tsena.

Lihlopha tsa equation

Lipotso tse ling tse amanang le karabelo ea lik'hemik'hale 2KOH + Na₂Cr₂O₇ → H₂O + Na₂CrO₄ + K₂CrO₄

Lipotso tse amanang le reactant KOH (potassium hydroxide)

Lipotso tse amanang le reactant Na2Cr2O7 (Sodium dichromate; sodium bichromate; Dichromic acid disodium letsoai)

Lipotso tse amanang le sehlahisoa H2O (metsi)

Lipotso tse amanang le sehlahisoa Na2CrO4 (Sodium chromate; Sodium chromate(VI); Chromic acid disodium letsoai)

Lipotso tse amanang le sehlahisoa K2CrO4 ()