Lethathamo la Tse ka Content

Tobetsa ho bona lintlha tse ling le ho bala boima ba 'mele / mol >>

KOH	+	2C₆H₅CHO	→	C₆H₅CH₂OH	+	C₆H₅PEKA
potasiamo hydroxide		benzaldehyde		benzyl joala		Potassium benzoate


1		2		1		1	Hệ số
							Nguyên - Phân tử khối (g / mol)
							Số mol
							Khối lượng (g)

Lintlha tse ling mabapi le equation KOH + 2C₆H₅CHO → C₆H₅CH₂OH + C₆H₅PEKA

Ke eng e etsang boemo ba KOH (potassium hydroxide) ka C6H5CHO (benzaldehyde) ?

Ha ho na tlhahisoleseling e fumanoeng bakeng sa equation ena ea lik'hemik'hale

Tlhaloso: Maemo a loketseng a tikoloho bakeng sa karabelo, joalo ka mocheso, khatello, li-catalysts, le solvent. Li-Catalysts ke lintho tse potlakisang lebelo (lebelo) la karabelo ea lik'hemik'hale ntle le ho jeoa kapa ho fetoha karolo ea sehlahisoa sa pheletso. Li-catalyst ha li na phello maemong a tekano.

Maikutlo a ka etsahala joang le ho hlahisa C6H5CH2OH (benzyl alcohol) le C6H5COOK (Potassium benzoate) ?

In a full sentence, you can also say KOH (potassium hydroxide) reacts with C6H5CHO (benzaldehyde) and produce C6H5CH2OH (benzyl alcohol) and C6H5COOK (Potassium benzoate)

Phenomenon after KOH (potassium hydroxide) reacts with C6H5CHO (benzaldehyde)

Tekano ena ha e na tlhahisoleseling efe kapa efe e mabapi le ketsahalo.

Maemong ana, o hloka feela ho sheba ho bona hore na ntho ea sehlahisoa ke eng C6H5COOK (Potassium benzoate), e hlahang qetellong ea karabelo.

Kapa haeba ho na le e 'ngoe ea lintho tse latelang tse sebetsang C6H5CHO (benzaldehyde), ea nyamela

Ke lintlha life tse ling tsa bohlokoa tseo u lokelang ho li tseba mabapi le karabelo

Ha re na lintlha tse ling mabapi le ts'ebetso ea lik'hemik'hale tsena.

Lihlopha tsa equation

Lipotso tse ling tse amanang le karabelo ea lik'hemik'hale KOH + 2C₆H₅CHO → C₆H₅CH₂OH + C₆H₅PEKA

Rating

KOH + 2C6H5CHO = C6H5CH2OH + C6H5COOK | Chemical Equation

Palo eohle ea linaleli tsa sengoloa sena ke: 5 in 1 tekolo botjha

Rating: 5 / 5 linaleli

Ho lekana le KOH joalo ka reactant

potasiamo hydroxide

2KOH + Mg (Che₃)₂ → 2KNO₃ + Mg (OH)₂ KOH + FeCl₃ → KCl + Fe (OH)₃ KOH + HLOKO₃ → CH₃OH + HLOKO Sheba li-equations tsohle le KOH joaloka reactant

Linomoro le C6H5CHO joalo ka reactant

benzaldehyde

C₆H₅CHO → C₆H₅-CH (OH) -Ph 2H₂ + C₆H₅CHO → H₂O + C₆H₅CH₃ KOH + 2C₆H₅CHO → C₆H₅CH₂OH + C₆H₅PEKA Sheba li-equation tsohle le C6H5CHO joalo ka reactant

Lipalo le C6H5CHO e le sehlahisoa

benzaldehyde

CuO + C₆H₅CH₂OH → Cu + H₂O + C₆H₅CHO C₆H₆ + CO → C₆H₅CHO Sheba li-equation tsohle le C6H5CHO e le sehlahisoa

Lipalo le C6H5CHO e le sehlahisoa

benzaldehyde

CuO + C₆H₅CH₂OH → Cu + H₂O + C₆H₅CHO C₆H₆ + CO → C₆H₅CHO Sheba li-equation tsohle le C6H5CHO e le sehlahisoa

KOH + C6H5CHO = C6H5CH2OH + C6H5COOK | Balanced | Chemical Reaction Details

potassium hydroxide + benzaldehyde = benzyl alcohol + Potassium benzoate |

Litaba Ke 5% feela ea BAAHI e tla tseba

Lintlha tse ling mabapi le equation KOH + 2C₆H₅CHO → C₆H₅CH₂OH + C₆H₅PEKA

Ke eng e etsang boemo ba KOH (potassium hydroxide) ka C6H5CHO (benzaldehyde) ?

Maikutlo a ka etsahala joang le ho hlahisa C6H5CH2OH (benzyl alcohol) le C6H5COOK (Potassium benzoate) ?

Phenomenon after KOH (potassium hydroxide) reacts with C6H5CHO (benzaldehyde)

Ke lintlha life tse ling tsa bohlokoa tseo u lokelang ho li tseba mabapi le karabelo

Lihlopha tsa equation

Lipotso tse ling tse amanang le karabelo ea lik'hemik'hale KOH + 2C₆H₅CHO → C₆H₅CH₂OH + C₆H₅PEKA

Lipotso tse amanang le reactant KOH (potassium hydroxide)

Lipotso tse amanang le reactant C6H5CHO (benzaldehyde)

Lipotso tse amanang le sehlahisoa C6H5CH2OH (benzyl alcohol)