Lethathamo la Tse ka Content
3H2SO4 | + | 4NaBr | → | Br2 | + | 2H2O | + | 2Na2SO4 | + | SO2 | + | 2HBR | |
acid e sulfuric | bromide ea sodium | bromine | metsi | sodium sulfate | sebabole dioxide | asiti ea hydrobromic | |||||||
(đặm đặc) | (rn) | (lng) | (lng) | (rn) | (khí) | (khí) | |||||||
(không màu) | (trắng) | (ha u đỏ) | (không màu) | (trắng) | (không màu, mùi sốc) | (không màu) | |||||||
3 | 4 | 1 | 2 | 2 | 1 | 2 | Hệ số | ||||||
Nguyên - Phân tử khối (g / mol) | |||||||||||||
Số mol | |||||||||||||
Khối lượng (g) |
Ha ho na tlhahisoleseling e fumanoeng bakeng sa equation ena ea lik'hemik'hale
Tlhaloso: Maemo a loketseng a tikoloho bakeng sa karabelo, joalo ka mocheso, khatello, li-catalysts, le solvent. Li-Catalysts ke lintho tse potlakisang lebelo (lebelo) la karabelo ea lik'hemik'hale ntle le ho jeoa kapa ho fetoha karolo ea sehlahisoa sa pheletso. Li-catalyst ha li na phello maemong a tekano.
Bromide ea sodium e itšoara ka H2SO4
In a full sentence, you can also say H2SO4 (sulfuric acid) reacts with NaBr (sodium bromide) and produce Br2 (bromine) and H2O (water) and Na2SO4 (sodium sulfate) and SO2 (sulfur dioxide) and HBr (hydrobromic acid)
Ha re na lintlha tse ling mabapi le ts'ebetso ea lik'hemik'hale tsena.
acid e sulfuric
H2SO4 + Na2SO3 → H2O + Na2SO4 + SO2 10OO + 18H2SO4 + 2KMnO4 → 5Fe2(NA4)3 + 18H2O + 2MNSO4 + K2SO4 Cu + 2H2SO4 → lihora tse 22O + SO2 + CuSO4 Sheba li-equation tsohle le H2SO4 e le reactantbromide ea sodium
8H2SO4 + 2KMnO4 + 10NaBr → 5Br2 + 8H2O + 2MNSO4 + 5Na2SO4 + K2SO4 Cl2 + 2NaBr → Br2 + 2NaCl 2H2SO4 + MnO2 + 2NaBr → Br2 + 2H2O + MnSO4 + Na2SO4 Sheba li-equations tsohle le NaBr joaloka reactantbromide ea sodium
NaOH + C6H5Br → C6H5ONa + H2O + NaBr Br2 + 2NaI → I2 + 2NaBr 2Br2 + 8NaOH + CrBr2 → lihora tse 42O + Na2CrO4 + 6NaBr Sheba li-equations tsohle le NaBr e le sehlahisoabromide ea sodium
NaOH + C6H5Br → C6H5ONa + H2O + NaBr Br2 + 2NaI → I2 + 2NaBr 2Br2 + 8NaOH + CrBr2 → lihora tse 42O + Na2CrO4 + 6NaBr Sheba li-equations tsohle le NaBr e le sehlahisoabromide ea sodium
NaOH + C6H5Br → C6H5ONa + H2O + NaBr Br2 + 2NaI → I2 + 2NaBr 2Br2 + 8NaOH + CrBr2 → lihora tse 42O + Na2CrO4 + 6NaBr Sheba li-equations tsohle le NaBr e le sehlahisoabromide ea sodium
NaOH + C6H5Br → C6H5ONa + H2O + NaBr Br2 + 2NaI → I2 + 2NaBr 2Br2 + 8NaOH + CrBr2 → lihora tse 42O + Na2CrO4 + 6NaBr Sheba li-equations tsohle le NaBr e le sehlahisoabromide ea sodium
NaOH + C6H5Br → C6H5ONa + H2O + NaBr Br2 + 2NaI → I2 + 2NaBr 2Br2 + 8NaOH + CrBr2 → lihora tse 42O + Na2CrO4 + 6NaBr Sheba li-equations tsohle le NaBr e le sehlahisoaTlhahisoleseling e khahlisang Ke batho ba fokolang feela ba tsebang
Lipapatso tsa foromo ea chelete li re thusa ho boloka litaba li le boleng bo holimo haholo hobaneng re hloka ho beha lipapatso? : D.
Ha ke batle ho tšehetsa sebaka sa marang-rang (koala) - :(