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C₆H₅OH	+	Na	→	C₆H₅ONa	+	1 / 2H₂
phenol		sodium				hydrogen
(lng)		(rn)		(rn)		(khí)
		(trắng bạc)				(không màu)
1		1		1		1 / 2	Hệ số
							Nguyên - Phân tử khối (g / mol)
							Số mol
							Khối lượng (g)

Lintlha tse ling mabapi le equation C₆H₅OH + Na → C₆H₅ONa + 1 / 2H₂

Ke eng e etsang hore C6H5OH (phenol) e sebetsane le Na (sodium)?

Ha ho na tlhahisoleseling e fumanoeng bakeng sa equation ena ea lik'hemik'hale

Tlhaloso: Maemo a loketseng a tikoloho bakeng sa karabelo, joalo ka mocheso, khatello, li-catalysts, le solvent. Li-Catalysts ke lintho tse potlakisang lebelo (lebelo) la karabelo ea lik'hemik'hale ntle le ho jeoa kapa ho fetoha karolo ea sehlahisoa sa pheletso. Li-catalyst ha li na phello maemong a tekano.

Ke joang likarabelo li ka etsahalang 'me tsa hlahisa C6H5ONa () le H2 (hydrogen) ?

Phenol e itšoara ka Na

In a full sentence, you can also say C6H5OH (phenol) reacts with Na (sodium) and produce C6H5ONa () and H2 (hydrogen)

Phenomenon kamora C6H5OH (phenol) e kopana le Na (sodium)

Tobetsa ho bona ts'ebetso ea equation

Ke lintlha life tse ling tsa bohlokoa tseo u lokelang ho li tseba mabapi le karabelo

Ha re na lintlha tse ling mabapi le ts'ebetso ea lik'hemik'hale tsena.

Lihlopha tsa equation

Lipotso tse ling tse amanang le karabelo ea lik'hemik'hale C₆H₅OH + Na → C₆H₅ONa + 1 / 2H₂

Rating

C6H5OH + Na = C6H5ONa + 1/2H2 | Equation ea lik'hemik'hale

Palo eohle ea linaleli tsa sengoloa sena ke: 5 in 1 tekolo botjha

Rating: 5 / 5 linaleli

Litekanyo le C6H5OH e le reactant

phenol

3Br₂ + C₆H₅OH → 3HBr + (Br)₃C₆H₂OH 2C₆H₅OH + 2Na → 2C₆H₅ONa + H₂ C₆H₅OH + Na → C₆H₅ONa + 1 / 2H₂ Sheba li-equations tsohle le C6H5OH joaloka reactant

Ho lekana le Na joalo ka reactant

sodium

Cl₂ + 2Na → 2NaCl 2H₂O + 2Na → H₂ + 2NaOH Na + C₂H₅COOH → H₂ + C₂H₅KOANNA Sheba li-equations tsohle le Na e le reactant

Litekanyo le Na e le sehlahisoa

sodium

C + 6NaOH → 3H₂ + 2Na + 2Na₂CO₃ 2NaCl → Cl₂ + 2Na 4NaOH → 2H₂O + 4Na + O₂ Sheba li-equations tsohle le Na e le sehlahisoa

Litekanyo le Na e le sehlahisoa

sodium

C + 6NaOH → 3H₂ + 2Na + 2Na₂CO₃ 2NaCl → Cl₂ + 2Na 4NaOH → 2H₂O + 4Na + O₂ Sheba li-equations tsohle le Na e le sehlahisoa

C6H5OH + Na = C6H5ONa + H2 | Balanced | Chemical Reaction Details

phenol + sodium = + hydrogen |

Litaba Ke 5% feela ea BAAHI e tla tseba

Lintlha tse ling mabapi le equation C₆H₅OH + Na → C₆H₅ONa + 1 / 2H₂

Ke eng e etsang hore C6H5OH (phenol) e sebetsane le Na (sodium)?

Ke joang likarabelo li ka etsahalang 'me tsa hlahisa C6H5ONa () le H2 (hydrogen) ?

Phenomenon kamora C6H5OH (phenol) e kopana le Na (sodium)

Ke lintlha life tse ling tsa bohlokoa tseo u lokelang ho li tseba mabapi le karabelo

Lihlopha tsa equation

Lipotso tse ling tse amanang le karabelo ea lik'hemik'hale C₆H₅OH + Na → C₆H₅ONa + 1 / 2H₂

Lipotso tse amanang le reactant C6H5OH (phenol)

Lipotso tse amanang le reactant Na (sodium)

Lipotso tse amanang le sehlahisoa C6H5ONA ()